I have a eq $\displaystyle 2y^2 + y + 1 = 0$

Now what i did was $\displaystyle 2y^2 + y + 1 -2 + 2 = 0$

$\displaystyle 2y^2 + y -1 +2 = 0$

$\displaystyle 2y^2 + y -1 = -2$

$\displaystyle (2y-1)(y+1) = -2$

$\displaystyle \therefore$ since $\displaystyle (2y - 1) = -2$

$\displaystyle y = \frac{-2 +1}{2}$ ..........Is this correct ?

& similarly

$\displaystyle y = -2-1 = -3$