log2 (x+1) + log2 (x-1) = 3 ..... log to base 2

Printable View

- Dec 22nd 2009, 07:57 PMmath321logs problem
log2 (x+1) + log2 (x-1) = 3 ..... log to base 2

- Dec 22nd 2009, 08:15 PMVonNemo19
Note that

$\displaystyle \log_bx+\log_by=\log_b(xy)$

And

$\displaystyle \log_bx=y$ if and only if $\displaystyle b^y=x$.

With these two propeties of logarithms, you should be able to solve this equation.