$\displaystyle 20000=Pe^{0.073*12}$ solve for p
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Originally Posted by math321 $\displaystyle 20000=Pe^{0.073*12}$ solve for p $\displaystyle P = \frac{20000}{e^{0.073(12)}}$ you should have asked this in your previous thread since it belongs to the same question ... http://www.mathhelpforum.com/math-he...-interest.html
Last edited by skeeter; Dec 21st 2009 at 03:18 PM.
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