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Math Help - logs problem

  1. #1
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    logs problem

    20000=Pe^{0.073*12}



    solve for p
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  2. #2
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    Quote Originally Posted by math321 View Post
    20000=Pe^{0.073*12}



    solve for p
    P = \frac{20000}{e^{0.073(12)}}


    you should have asked this in your previous thread since it belongs to the same question ...

    http://www.mathhelpforum.com/math-he...-interest.html
    Last edited by skeeter; December 21st 2009 at 03:18 PM.
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