$\displaystyle 20000=Pe^{0.073*12}$

solve for p

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- Dec 21st 2009, 02:36 PMmath321logs problem
$\displaystyle 20000=Pe^{0.073*12}$

solve for p - Dec 21st 2009, 03:07 PMskeeter
$\displaystyle P = \frac{20000}{e^{0.073(12)}}$

you should have asked this in your previous thread since it belongs to the same question ...

http://www.mathhelpforum.com/math-he...-interest.html