# logs problem

• December 21st 2009, 02:36 PM
math321
logs problem
$20000=Pe^{0.073*12}$

solve for p
• December 21st 2009, 03:07 PM
skeeter
Quote:

Originally Posted by math321
$20000=Pe^{0.073*12}$

solve for p

$P = \frac{20000}{e^{0.073(12)}}$

you should have asked this in your previous thread since it belongs to the same question ...

http://www.mathhelpforum.com/math-he...-interest.html