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December 21st 2009, 02:36 PM
math321

logs problem

$20000=Pe^{0.073*12}$

solve for p
December 21st 2009, 03:07 PM
skeeter

Quote:

Originally Posted by math321

$20000=Pe^{0.073*12}$

solve for p

$P = \frac{20000}{e^{0.073(12)}}$

you should have asked this in your previous thread since it belongs to the same question ...

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