logarithmic problem

5e^.2x=7

first just need to clarify do you mean

or

Quote:

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Originally Posted by math321

5e^.2x=7

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Hint: if , then taking natural logarithm on both sides we get , provided, of course,

Tonio

the second sum


and i want to find out...instead of I using the up arrow how do i get someting raised to a power

ln(5e^.2x) = ln7

is



so or

use latex to get the power

x^2 then highlight the expression with icon and you get after it is compiled in preview or after saving and posting

thanks alot

i got an exam tomoro so i am just practicing