5e^.2x=7

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- December 21st 2009, 10:26 AMmath321logarithmic problem
5e^.2x=7

- December 21st 2009, 10:36 AMbigwave
first just need to clarify do you mean

or - December 21st 2009, 10:38 AMtonio
- December 21st 2009, 10:42 AMmath321
the second sum

and i want to find out...instead of I using the up arrow how do i get someting raised to a power - December 21st 2009, 10:57 AMbigwave
ln(5e^.2x) = ln7

is

so or

use latex to get the power

x^2 then highlight the expression with icon and you get after it is compiled in preview or after saving and posting - December 21st 2009, 11:06 AMmath321
thanks alot

i got an exam tomoro so i am just practicing