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Math Help - Graphing Periods, Asymptotes and End Points

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    Graphing Periods, Asymptotes and End Points

    So the problem states to graph one complete period for f(x) = tan(3x - pi/2).

    So that becomes f(x) = tan 3(x - pi/6).

    Period = pi / 3
    Phase shift = pi / 6

    How do I get the end points / asymptotes? This is a pretty easy question, but I must not be getting something.

    I have the answers as x = 0, and x = pi / 3.

    I also see that for a basic curve, the end points are x = -pi / 2, and x = pi / 2, and when it shifts they become x = 0 and x = pi / 3.

    Thank you for helping me on this easy problem
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    Quote Originally Posted by NYKnicks View Post
    So the problem states to graph one complete period for f(x) = tan(3x - pi/2).

    So that becomes f(x) = tan 3(x - pi/6).

    Period = pi / 3
    Phase shift = pi / 6

    How do I get the end points / asymptotes? This is a pretty easy question, but I must not be getting something.

    I have the answers as x = 0, and x = pi / 3.

    I also see that for a basic curve, the end points are x = -pi / 2, and x = pi / 2, and when it shifts they become x = 0 and x = pi / 3.

    Thank you for helping me on this easy problem
    1 period of y = \tan{x} is from -\frac{\pi}{2} < x < \frac{\pi}{2}

    period transforms from \pi to \frac{\pi}{3}

    period for t = \tan(3x) is from -\frac{\pi}{6} < x < \frac{\pi}{6}

    shift the above period to the right \frac{\pi}{6} units ...

    -\frac{\pi}{6} + \frac{\pi}{6} < x < \frac{\pi}{6} + \frac{\pi}{6}<br />

    new period ...

    0 < x < \frac{\pi}{3}
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