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Math Help - Am I right?

  1. #1
    Member
    Joined
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    Am I right?

    Write the following expression as one logarithm:
    2 logx - log4 - log3 + logx

    My work:
    logx^4 - log4/3
    log (x^4) / (4/3)
    log (3x^4/4)

    I am not sure if this is correct because I was uncertain whether to multiply the -log4 and -log3 or divide them.

    Thanks for any help.
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  2. #2
    Senior Member
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    Smile

    Quote Originally Posted by iluvmathbutitshard View Post
    Write the following expression as one logarithm:
    2 logx - log4 - log3 + logx

    My work:
    logx^4 - log4/3
    log (x^4) / (4/3)
    log (3x^4/4)

    I am not sure if this is correct because I was uncertain whether to multiply the -log4 and -log3 or divide them.

    Thanks for any help.
    hi
    2 \log x - \log 4 - \log 3 + \log x = 3\log x - (\log 4 + \log 3) = \log {x^3} - \log{12} = \log{\frac{x^3}{12}}
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by iluvmathbutitshard View Post
    Write the following expression as one logarithm:
    2 logx - log4 - log3 + logx

    My work:
    logx^4 - log4/3
    log (x^4) / (4/3)
    log (3x^4/4)

    I am not sure if this is correct because I was uncertain whether to multiply the -log4 and -log3 or divide them.

    Thanks for any help.
    2 \log(x) - \log(4) - \log(3) + \log(x) = \log(x^2) + \log(1/4) + \log(1/3) + \log(x) =\log(x^3/(4\times 3))

    CB
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