# How do I solve this?

• December 18th 2009, 11:54 AM
iluvmathbutitshard
How do I solve this?
The question wants me to solve:
3^(x+2) - 4 = 12

So:
3^(x+2) = 8

What do I do next?

Any help is appreciated.
• December 18th 2009, 12:02 PM
Dinkydoe
I hope you are familiar with logarithms

Anyway: Observe that log(8)/log(3) = x+2
And this is equivalent to: log(8)/log(3)-2 = x
• December 18th 2009, 12:30 PM
JSB1917
Quote:

Originally Posted by iluvmathbutitshard
The question wants me to solve:
3^(x+2) - 4 = 12

So:
3^(x+2) = 8

What do I do next?

Any help is appreciated.

$3^{x+2} - 4 = 12$

Ok....hopefully this helps and you know the log properties

$3^{x+2}= 16$

$\ln3^{x+2} = \ln 16$

$(x+2)\ln3 = \ln 16$

This is one way, a little longer...

$x\ln3+2\ln3 = \ln 16$

$x\ln3 = \ln 16 - 2\ln3$

$x\ln3 = \ln (\frac{16}{9})$

$x= \frac{\ln (\frac{16}{9})}{\ln3}$

Or going back to the line before my comment....

$(x+2)\ln3 = \ln 16$

$x+2 = \frac{\ln 16}{\ln3}$

$x = \frac{\ln 16}{\ln3}-2$

and both....

$x = \frac{\ln 16}{\ln3}-2$ and $x= \frac{\ln (\frac{16}{9})}{\ln3}$ = .5237190143....
• December 18th 2009, 12:34 PM
iluvmathbutitshard
Thank you so much. This really helps. :)