Sorry, first post here, try my best! a_n=log((n+5)/(n+6)) I understand how to do partial sums and all but throwing a log in there has stopped me in my tracks. Please help!
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Originally Posted by lukestheboy Sorry, first post here, try my best! a_n=log((n+5)/(n+6)) I understand how to do partial sums and all but throwing a log in there has stopped me in my tracks. Please help! Since $\displaystyle \log \frac{n + 5}{n + 6} = \log (n + 5) - \log (n + 6)$ the partial sum will simplify to only two terms.
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