i don't know if i did this right...
sketch 2x^2 +12x -14 and indicate all its vertex and intercepts
my vertex tht i got is (-3,-26)
my y-intercept is (0,-14) x-intercept (-1,0) and (7,0)
is this right?
One method of finding the minimum of the graph is to convert it to turning point form by completing the square:
You can now see that the minimum is at
Now to find the x-intercepts let
Therefore the x-axis intercepts are at and
The y-intercept occurs where which is at
You should post your working so we can see where you went wrong.