# Math Help - Product Rule Question

1. ## Product Rule Question

Hi
I would like some help on solving this problem:
This is what i have done so far:
$3x(2x-1)^3$
$u=3x$
$v=(2x-1)^3$
$3(2x-1)^3+(6(2x-1)^2)(3x)$
$(2x-1)^3+8(2x-1)^2(3x)$
This is where i get stuck.

P.S

2. Originally Posted by Paymemoney
Hi
I would like some help on solving this problem:
This is what i have done so far:
$3x(2x-1)^3$
$u=3x$
$v=(2x-1)^3$
$3(2x-1)^3+(6(2x-1)^2)(3x)$
$(2x-1)^3+8(2x-1)^2(3x)$
This is where i get stuck.

P.S
You can continue by factoring out (2x - 1)²:

$(2x-1)^3+8(2x-1)^2(3x) = (2x-1)^2(2x-1+24x) = \boxed{(2x-1)^2 (26x-1)}$