how do i solve this equation? log3(x^2)-log3(3x+2)=0 if i cube the logs does that undo them?
Follow Math Help Forum on Facebook and Google+
Originally Posted by teddyryan how do i solve this equation? log3(x^2)-log3(3x+2)=0 if i cube the logs does that undo them? Rewrite the equation: Now use the LHS and the RHS as exponents to the base 3: This is a quadratic equation. Use the quadratic formula to solve this equation. You'll get 2 solutions, but be careful: One isn't valid. Why?
it wont be valid if its negative correct? logarithms have a vertical asymptote at 0
Originally Posted by teddyryan it wont be valid if its negative correct? logarithms have a vertical asymptote at 0 Correct on the negative part but it's a horizontal asymptote at x=0
Uhh, no, the y-axis is vertical!
View Tag Cloud