1. ## Logarithims

Solve for x

Logx=0.25

Log(0.25)=-x
-0.6020/-1= -x/-1
0.6920=x

The answer is suppose to be 1.78

2. Originally Posted by Skoz
Solve for x

Logx=0.25

Log(0.25)=-x
-0.6020/-1= -x/-1
0.6920=x

The answer is suppose to be 1.78
Is this a natural logarithm? As in, base $e$?

If so, exponentiate both sides

$\log{x} = 0.25$

$e^{\log{x}} = e^{0.25}$

$x = e^{0.25}$.

If it is a different base, replace $e$ with whatever the base is...

3. Assuming this is your original problem...

$\log {x} = 0.25$

Then it is merely, $10^{0.25}$ because

If $\log_a{b} = x$ then $a^x = b$

And $10^{0.25} = 1.77827941$