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Math Help - Logarithims

  1. #1
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    Logarithims

    Solve for x

    Logx=0.25

    Log(0.25)=-x
    -0.6020/-1= -x/-1
    0.6920=x

    The answer is suppose to be 1.78
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  2. #2
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    Quote Originally Posted by Skoz View Post
    Solve for x

    Logx=0.25

    Log(0.25)=-x
    -0.6020/-1= -x/-1
    0.6920=x

    The answer is suppose to be 1.78
    Is this a natural logarithm? As in, base e?

    If so, exponentiate both sides

    \log{x} = 0.25

    e^{\log{x}} = e^{0.25}

    x = e^{0.25}.


    If it is a different base, replace e with whatever the base is...
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  3. #3
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    Assuming this is your original problem...

    \log {x} = 0.25

    Then it is merely, 10^{0.25} because

    If \log_a{b} = x then a^x = b

    And 10^{0.25} = 1.77827941
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