Solve for x Logx=0.25 Log(0.25)=-x -0.6020/-1= -x/-1 0.6920=x The answer is suppose to be 1.78
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Originally Posted by Skoz Solve for x Logx=0.25 Log(0.25)=-x -0.6020/-1= -x/-1 0.6920=x The answer is suppose to be 1.78 Is this a natural logarithm? As in, base $\displaystyle e$? If so, exponentiate both sides $\displaystyle \log{x} = 0.25$ $\displaystyle e^{\log{x}} = e^{0.25}$ $\displaystyle x = e^{0.25}$. If it is a different base, replace $\displaystyle e$ with whatever the base is...
Assuming this is your original problem... $\displaystyle \log {x} = 0.25$ Then it is merely, $\displaystyle 10^{0.25}$ because If $\displaystyle \log_a{b} = x$ then $\displaystyle a^x = b$ And $\displaystyle 10^{0.25} = 1.77827941$
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