i don't know how to do this identity:
tan ^4-sec^4=...
can you help me? i hope not to disturb you..but i'm reviewing 2 chapters made so far...and i truly need your help.
i would ike that u help me on doing these ones too...
sec^4 - 2 sec^2tan^2+ tan^4=
sec sin / tan -1
use a right triangle to write the expression as an algebraic expression. Assume that v is positive and in the domainof the given inverse trigonometric function.
8)cos ( inverse sin v )
9) sin (inverse sec square root of v^2+9/v) . The possible choices are :
a)v square root of v^2 +3/v^2+3
b) v suqare root of v^2/2
c) 3 square root of v^2 + 9 / v^2 +9
d) square root of v^2 +3/v^2+3
find the exact value of
inverse cos ( cos (-3 radian / 5) )
i have to do a test to catch up and raise my grades...really that you guys help me!