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Math Help - maths - parabola

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    maths - parabola

    The equation of a parabola is given by x^2 - 4x - 2y + 8 = 0
    find the vertex, the focus and the equation of the normal to the parabola at the point (0,4)
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    Quote Originally Posted by deej813 View Post
    The equation of a parabola is given by x^2 - 4x - 2y + 8 = 0
    find the vertex, the focus and the equation of the normal to the parabola at the point (0,4)
    Transform the given equation into the form

    4p(y-h)=(x-k)^2 by completing the square.

    Then the vertex is at V(k, h).

    The focus is at F(k, h+p)

    Calculate the slope of the tangent at (0, 4) and afterwards calculate the perpendicular direction.
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