The equation of a parabola is given by x^2 - 4x - 2y + 8 = 0
find the vertex, the focus and the equation of the normal to the parabola at the point (0,4)
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The equation of a parabola is given by x^2 - 4x - 2y + 8 = 0
find the vertex, the focus and the equation of the normal to the parabola at the point (0,4)
Transform the given equation into the formQuote:
Originally Posted by deej813
by completing the square.
Then the vertex is at V(k, h).
The focus is at F(k, h+p)
Calculate the slope of the tangent at (0, 4) and afterwards calculate the perpendicular direction.