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Math Help - Rectangular Beam

  1. #1
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    Rectangular Beam

    The maximum safe load that a rectangular beam can support varies directly with the width w and the square of the height h and inversely with the length L of the beam. A 6-foot-long beam that is 2 inches high and 4 inches wide has a maximum safe load of 1000 pounds.

    (a) What is the maximum safe load for a 10-foot-long beam that is 4 inches high and 4 inches wide?

    (b) How long should a 4 inch beam be to safely support a 6000-pound load?
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  2. #2
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    Quote Originally Posted by sologuitar View Post
    The maximum safe load that a rectangular beam can support varies directly with the width w and the square of the height h and inversely with the length L of the beam.
    Translating this directly into an equation, I get

    M = k \frac{wh^2}{L}

    where k is a proportionality constant that you have to determine from the data you've been given. That is, they've given you M, w, h, and L in one case, and you have to figure out k for that case.

    Once you know k, you can use it to solve for any of the unknown situations.
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  3. #3
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    Good...

    Quote Originally Posted by Haversine View Post
    Translating this directly into an equation, I get

    M = k \frac{wh^2}{L}

    where k is a proportionality constant that you have to determine from the data you've been given. That is, they've given you M, w, h, and L in one case, and you have to figure out k for that case.

    Once you know k, you can use it to solve for any of the unknown situations.
    Thanks for the tips. I can take it from here.
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