The question asks: Solve for h A=1/2h (b1+b2) I think the solution is h= 2A/(b1+b2) Is this correct?
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Originally Posted by KarlosK The question asks: Solve for h A=1/2h (b1+b2) I think the solution is h= 2A/(b1+b2) Is this correct? Indeed you are assuming the original equation is $\displaystyle A = \frac{1}{2}h(b_1+b_2)$
Yes that is what the original equation was. I am not very good at typing the problems out correctly in here!! So I did it correctly?
Originally Posted by KarlosK Yes that is what the original equation was. I am not very good at typing the problems out correctly in here!! So I did it correctly? You did
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