here's another i can't solve.

t - 5√t - 14 = 0

i added 14 to both sides and then squared them. then i minused 196 and am left with t^2 + 15t -196 = 0

this doesn't work, what have i done wrong?

2. Originally Posted by Miasmagasma
here's another i can't solve.

t - 5√t - 14 = 0

i added 14 to both sides and then squared them. then i minused 196 and am left with t^2 + 15t -196 = 0

this doesn't work, what have i done wrong?
$t-14 = 5\sqrt{t}$

$t^2 - 28t + 196 = 25t$

$t^2 - 53t + 196 = 0$

3. Originally Posted by skeeter
$t-14 = 5\sqrt{t}$

$t^2 - 28t + 196 = 25t$

$t^2 - 53t + 196 = 0$
cheers but why did my method not work?

4. Originally Posted by Miasmagasma
cheers but why did my method not work?
Because $(t - 5 \sqrt{t})^2 \neq t^2 + 15t$. If you post all your working on how you got that (wrong) result your error(s) can be explained.

5. Originally Posted by mr fantastic
Because $(t - 5 \sqrt{t})^2 \neq t^2 + 15t$. If you post all your working on how you got that (wrong) result your error(s) can be explained.
well i thought t times 5√t = 5t which is no doubt wrong. how do you work that out?

6. Originally Posted by Miasmagasma
here's another i can't solve.

t - 5√t - 14 = 0

i added 14 to both sides and then squared them. then i minused 196 and am left with t^2 + 15t -196 = 0

this doesn't work, what have i done wrong?
Notice it looks very much like a quadratic.

So use a dummy variable $x^2 = t$.

This would mean $x = \sqrt{t}$.

$x^2 - 5x - 14 = 0$

$(x - 7)(x + 2) = 0$

$x = -2$ or $x = 7$.

Note that, since $\sqrt{t} = x$, the solution $x = -2$ is unusable.

This means, since $t = x^2$, that $t = 49$.

7. Originally Posted by Miasmagasma
well i thought t times 5√t = 5t which is no doubt wrong. how do you work that out?
How can $t \cdot 5 \sqrt{t} = 5t$? If t = 4 do you get a correct result from this? And what then do you think $\sqrt{t} \cdot 5 \sqrt{t}$ is equal to?

8. As you surmised, $t * 5\sqrt{t} \neq 5t$. On the other hand, $\sqrt{t} * 5\sqrt{t} = 5t$.