'How can you get "very close" to Log(7) if you knew Log(2) and Log(3)? I'm still wondering about this; if anyone gets close.. just tell me and I'll tweak your answer more. Thanks in advance!
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Originally Posted by .Masta X 'How can you get "very close" to Log(7) if you knew Log(2) and Log(3)? I'm still wondering about this; if anyone gets close.. just tell me and I'll tweak your answer more. Thanks in advance! Hint: Remember that
Hello, Masta X! How can you get "very close" to Log(7) if you knew Log(2) and Log(3)? Is this close enough? We have: . Therefore: .
Yes, Soroban! I got something like that, but I was off by 0.0020. Thank you very much! I really appreciate your help greatly!
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