I can't solve this easy question ? (Doh)

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- Dec 7th 2009, 07:22 AMr-soyI can't solve this easy question ?
I can't solve this easy question ? (Doh)

- Dec 7th 2009, 08:20 AMMush
You can't cancel out like that.

Remember that $\displaystyle \csc(x) = \frac{1}{\sin(x)} $

Therefore, try this:

$\displaystyle \frac{\sin(x) + \cos^2(x)}{\sin(x)} = \csc(x) $

$\displaystyle \sin(x) + \cos^2(x) = \frac{1}{\sin(x)} \times \sin(x) $

$\displaystyle \sin(x) + \cos^2(x) = 1 $

Now, remember that $\displaystyle sin^2(x) + cos^2(x) = 1 $. You can use this to write $\displaystyle \cos^2(x) $ in terms of $\displaystyle \sin(x) $ which will give you a quadratic in $\displaystyle \sin(x) $ to solve. - Dec 7th 2009, 11:00 AMr-soy
Are you now solve the question ?

we take LHS or RHS ?

help me - Dec 8th 2009, 01:57 AMmr fantastic