# I can't solve this easy question ?

• December 7th 2009, 08:22 AM
r-soy
I can't solve this easy question ?
I can't solve this easy question ? (Doh)
• December 7th 2009, 09:20 AM
Mush
Quote:

Originally Posted by r-soy
I can't solve this easy question ? (Doh)

You can't cancel out like that.

Remember that $\csc(x) = \frac{1}{\sin(x)}$

Therefore, try this:

$\frac{\sin(x) + \cos^2(x)}{\sin(x)} = \csc(x)$

$\sin(x) + \cos^2(x) = \frac{1}{\sin(x)} \times \sin(x)$

$\sin(x) + \cos^2(x) = 1$

Now, remember that $sin^2(x) + cos^2(x) = 1$. You can use this to write $\cos^2(x)$ in terms of $\sin(x)$ which will give you a quadratic in $\sin(x)$ to solve.
• December 7th 2009, 12:00 PM
r-soy
Are you now solve the question ?

we take LHS or RHS ?

help me
• December 8th 2009, 02:57 AM
mr fantastic
Quote:

Originally Posted by r-soy
Are you now solve the question ?

we take LHS or RHS ?

help me

You have been told what to do. You're expected to show some effort now. If still you're still stuck, please say exactly where you're stuck.

(By the way ... it's an equation NOT and identity. You have to solve for x).