Suppose a, b, and c are fixed real numbers such that b^2 - 4ac ≥ 0. Let r and s be the solutions of ax^2 + bx + x = 0. (a) Use the quadratic formula to show that r + s = -b/a and rs = c/a.
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Originally Posted by sologuitar Suppose a, b, and c are fixed real numbers such that b^2 - 4ac ≥ 0. Let r and s be the solutions of ax^2 + bx + x = 0. (a) Use the quadratic formula to show that r + s = -b/a and rs = c/a. Comparing coefficients gives and Hope this helps!
Originally Posted by sologuitar Suppose a, b, and c are fixed real numbers such that b^2 - 4ac ≥ 0. Let r and s be the solutions of ax^2 + bx + x = 0. (a) Use the quadratic formula to show that r + s = -b/a and rs = c/a. r,s are roots of the equation so we can write the equation like this
Oh, this was a! I did the problems in the wrong order!
Originally Posted by Amer r,s are roots of the equation so we can write the equation like this I would have not been able to work my way through this question.
Originally Posted by BabyMilo Comparing coefficients gives and Hope this helps! This question is interestingly hard.
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