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Math Help - Introduction to CONICS

  1. #1
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    Introduction to CONICS

    Find the vertex,focus, and directrix of the parabola. Use a graphing utility to graph the parabola.

    Y^2-4x-4=0
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  2. #2
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    Quote Originally Posted by VNVeteran View Post
    Find the vertex,focus, and directrix of the parabola. Use a graphing utility to graph the parabola.

    Y^2-4x-4=0

    I'm guessing this is what you need to do: comparing y^2=4x+4 with y^2 = 4ax shows that a=1, so the focus is S(1,0). Find coordinates of one point on the curve to identify it. For example if x=2 then y^2 =12 and y = \sqrt{12}
    And of course, the equation of the fixed line (directrix) is x=-a.
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