Find the vertex,focus, and directrix of the parabola. Use a graphing utility to graph the parabola.
Y^2-4x-4=0
I'm guessing this is what you need to do: comparing with shows that a=1, so the focus is S(1,0). Find coordinates of one point on the curve to identify it. For example if x=2 then and
And of course, the equation of the fixed line (directrix) is x=-a.