Hello, ^_^Engineer_Adam^_^!

I have no idea why they placed the origin that way . . . very inconsiderate!

Listening post are at A, B, and C.

Point A is 2000ft north of point B, and point C is 2000ft east of B.

The sound of a gun reaches A and B simultaneously one second after it reaches C.

Show that the coordinates of a gun's position are approximately (*1860*,1000),

where *the origin is at B*. .Assume that sound travels 1100ft/sec Code:

A *
|*
| *
| *
| * d+1100
| *
2000 | *
| * G
| *(x,y)
| * * d+1100
| *d *
| * *
* - - - - - - - - - - - *
B 2000 C

The gun is at G(x,y).

Let GB = d. .Then GA = GC = d + 1100

Since G is equidistant from A and C, it lies on the 45°-line: x = y

The distance from G(x,x) to B(0,0) is: .√(2x²) .= .d

The distance from G(x,x) to C(2000,0) is: .√[(x - 2000)² + x²] .= .d + 1100

And we have this system of equations:

. . . . . . . . . . . 2x² .= .d²

. . (x - 2000)² + x² .= .(d + 1100)²

*Good luck!*