I need to find the formula for the general term in the given sequences:
---------And---------
I'm not sure how to approach this, I've looked for common differences, would it work if I used this: ?
Thank you, I appreciate your help!
I need to find the formula for the general term in the given sequences:
---------And---------
I'm not sure how to approach this, I've looked for common differences, would it work if I used this: ?
Thank you, I appreciate your help!
Thank you for the first one!
As for the second, the first term corresponds to n=1, the second to n=2, etc. When n=1 your formula: n/(n-1)^2 actually divides by zero, and when n=2 it gives you 1.
So it just needed to be adjusted to (n+2)/(n+1)^2.
Thank you so much, you got me thinking on the right track.
incorrect, the formula provided for the second sequence was
$\displaystyle \frac{1}{3n}~,n= 1,2,3,\dots$
For $\displaystyle n=1:~ \frac{1}{3\times 1}=\frac{1}{3} $ as required
Incorrect again.
For $\displaystyle n=2:~ \frac{1}{3\times 2}=\frac{1}{6} $ as required
My bad, I misdirected you. I meant to thank you for the formula pertaining to the second sequence: However, as for the first sequence, I had to modify to in order for it to work when n=1 and n=2. When n=1 your formula actually divides by zero, and when n=2 it produced 1.
Sorry for the inconvenience!