Hi

I'm having trouble finding the turning point(max & min) of this equation and also the stationary points and x-intercepts.

P.S

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- Dec 2nd 2009, 02:05 PMPaymemoneyFinding the turning point
Hi

I'm having trouble finding the turning point(max & min) of this equation and also the stationary points and x-intercepts.

P.S - Dec 2nd 2009, 02:24 PMBacterius
The x-intercepts are the points where the curve hits the x-axis. Do you mean you have trouble solving for ?

Think about using the derivative. When the derivative is in a point, the function is very likely to turn round at this point (although sometimes it doesn't).

Steps :

- get the derivative of your function

- solve for with

- ensure each point found is indeed a turning point (you should know how to do this last step)

Does it make sense ? - Dec 2nd 2009, 05:29 PMPaymemoney
yeh it makes sense, thanks for the help