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Math Help - Standard equation

  1. #1
    Member purplec16's Avatar
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    Standard equation

    Find the standard equation of the parabola with vertical axis, that has vertex (3,-2) and passes through the point (5,4).

    Is it y=5/4(x-3)^3-2?
    Last edited by purplec16; December 2nd 2009 at 01:02 PM.
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by purplec16 View Post
    Find the standard equation of the parabola with vertical axis, that has vertex (3,-2) and passes through the point (5,4).

    What do i do?
    Hi purplec16,

    The standard (vertex) form of your parabola is:

    y=a(x-h)^2+k

    (h, k) is your vertex which is (3, -2)

    (x, y) is a point on the curve which is (5, 4)

    Substitute this information into the vertex equation to solve for a.

    4=a(5-3)^2-2

    a=\frac{3}{2}

    Put it all back together again to get:

    y=\frac{3}{2}(x-3)^2-2
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