# Math Help - Standard equation

1. ## Standard equation

Find the standard equation of the parabola with vertical axis, that has vertex (3,-2) and passes through the point (5,4).

Is it y=5/4(x-3)^3-2?

2. Originally Posted by purplec16
Find the standard equation of the parabola with vertical axis, that has vertex (3,-2) and passes through the point (5,4).

What do i do?
Hi purplec16,

The standard (vertex) form of your parabola is:

$y=a(x-h)^2+k$

(h, k) is your vertex which is (3, -2)

(x, y) is a point on the curve which is (5, 4)

Substitute this information into the vertex equation to solve for a.

$4=a(5-3)^2-2$

$a=\frac{3}{2}$

Put it all back together again to get:

$y=\frac{3}{2}(x-3)^2-2$