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Math Help - Asymptotes

  1. #1
    Member purplec16's Avatar
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    Asymptotes

    Given the function

    R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}
    Find the
    domain of R.
    x-intercepts
    y-intercepts
    Vertical Asymptote(s)
    Horizontal Asymptote

    im completely confused
    this is what i got so far
    domian= {x|x is not equal to 3 or -2}
    x-intercepts=x=-3 and x=2
    y-intercepts= 1
    vertical asymptotes(s)= 1
    horizontal asymptote= -2
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  2. #2
    MHF Contributor
    skeeter's Avatar
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    Quote Originally Posted by purplec16 View Post
    Given the function

    R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}
    Find the
    domain of R.
    x-intercepts
    y-intercepts
    Vertical Asymptote(s)
    Horizontal Asymptote

    im completely confused
    this is what i got so far

    domian= {x|x is not equal to 3 or -2} correct

    x-intercepts=x=-3 and x=2 correct

    y-intercepts= 1 correct

    vertical asymptotes(s)= 1 no ... x = 3 and x = -2


    horizontal asymptote= -2 no again ... y = 1
    http://www.purplemath.com/modules/asymtote4.htm
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  3. #3
    Member purplec16's Avatar
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    i dont understand how you find the horizontal and vertical asymptote
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  4. #4
    MHF Contributor
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    Quote Originally Posted by purplec16 View Post
    i dont understand how you find the horizontal and vertical asymptote
    did you look at the link lesson I provided?
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  5. #5
    Member purplec16's Avatar
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    yes I got a better understand but I dont completely get it
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