# Asymptotes

• Dec 2nd 2009, 07:41 AM
purplec16
Asymptotes
Given the function

$R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}$
Find the
domain of R.
x-intercepts
y-intercepts
Vertical Asymptote(s)
Horizontal Asymptote

im completely confused
this is what i got so far
domian= {x|x is not equal to 3 or -2}
x-intercepts=x=-3 and x=2
y-intercepts= $1$
vertical asymptotes(s)= $1$
horizontal asymptote= $-2$
• Dec 2nd 2009, 08:04 AM
skeeter
Quote:

Originally Posted by purplec16
Given the function

$R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}$
Find the
domain of R.
x-intercepts
y-intercepts
Vertical Asymptote(s)
Horizontal Asymptote

im completely confused
this is what i got so far

domian= {x|x is not equal to 3 or -2} correct

x-intercepts=x=-3 and x=2 correct

y-intercepts= $1$ correct

vertical asymptotes(s)= $1$ no ... x = 3 and x = -2

horizontal asymptote= $-2$ no again ... y = 1

http://www.purplemath.com/modules/asymtote4.htm
• Dec 2nd 2009, 08:35 AM
purplec16
i dont understand how you find the horizontal and vertical asymptote
• Dec 2nd 2009, 12:00 PM
skeeter
Quote:

Originally Posted by purplec16
i dont understand how you find the horizontal and vertical asymptote

did you look at the link lesson I provided?
• Dec 2nd 2009, 12:21 PM
purplec16
yes I got a better understand but I dont completely get it