# Asymptotes

• Dec 2nd 2009, 06:41 AM
purplec16
Asymptotes
Given the function

$\displaystyle R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}$
Find the
domain of R.
x-intercepts
y-intercepts
Vertical Asymptote(s)
Horizontal Asymptote

im completely confused
this is what i got so far
domian= {x|x is not equal to 3 or -2}
x-intercepts=x=-3 and x=2
y-intercepts=$\displaystyle 1$
vertical asymptotes(s)=$\displaystyle 1$
horizontal asymptote=$\displaystyle -2$
• Dec 2nd 2009, 07:04 AM
skeeter
Quote:

Originally Posted by purplec16
Given the function

$\displaystyle R(x)=\frac{(x+3)(x-2)}{(x-3)(x+2)}$
Find the
domain of R.
x-intercepts
y-intercepts
Vertical Asymptote(s)
Horizontal Asymptote

im completely confused
this is what i got so far

domian= {x|x is not equal to 3 or -2} correct

x-intercepts=x=-3 and x=2 correct

y-intercepts=$\displaystyle 1$ correct

vertical asymptotes(s)=$\displaystyle 1$ no ... x = 3 and x = -2

horizontal asymptote=$\displaystyle -2$ no again ... y = 1

http://www.purplemath.com/modules/asymtote4.htm
• Dec 2nd 2009, 07:35 AM
purplec16
i dont understand how you find the horizontal and vertical asymptote
• Dec 2nd 2009, 11:00 AM
skeeter
Quote:

Originally Posted by purplec16
i dont understand how you find the horizontal and vertical asymptote

did you look at the link lesson I provided?
• Dec 2nd 2009, 11:21 AM
purplec16
yes I got a better understand but I dont completely get it