cube root of 16(m^2)(n) multiplied by cube root of 27(m^2)(n)

I converted the problem to (16m^2n)^1/3 * (27m^2n)^/3.

Is this the correct way to write the original problem another way?

I finally got (432m^4n^2)^2/3.

Is this correct?

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- Nov 30th 2009, 09:03 AMsharkmanCube Root times Cube Root
cube root of 16(m^2)(n) multiplied by cube root of 27(m^2)(n)

I converted the problem to (16m^2n)^1/3 * (27m^2n)^/3.

Is this the correct way to write the original problem another way?

I finally got (432m^4n^2)^2/3.

Is this correct? - Nov 30th 2009, 09:15 AMcraig
- Nov 30th 2009, 09:26 AMsharkmananswer...
- Nov 30th 2009, 09:27 AMcraig
Correct :)

- Nov 30th 2009, 09:28 AMsharkmangreat
- Dec 1st 2009, 03:04 AMHallsofIvy
- Dec 1st 2009, 06:03 AMsharkmanok