hi all. i've been stuck on this logarithm question for a while now, and i just can't seem to get the answer.

the question is

$\displaystyle e^(4x^2 - 2) = 3$

(the 4x^2 - 2 is supposed to be the power of e)

solve for x to 2 decimals.

anyways, i keep on getting a positive and negative number answer, but it's the incorrect value. i get like +- 0.88 , so i'm just curious as to how i can solve this question.

thank you very much