# Math Help - polar coordinate conversion.

1. ## polar coordinate conversion.

find polar coordinates of the points whose cartesian coordinates are given.

heres the point: (3sqrt(3), 3)

well i know that r^2 = (sqrt(a^2 + b^2))
so the answer here is : 6

and if we use tan(theta) = o/a = 3/(3sqrt(3)
so the answer here is: 1/sqrt(3)

so theta is pi/6

so how do i know its pi/6?
how do i convert to get this answer with pi? radians?

2. Hello, rcmango!

Find polar coordinates of the point . . _
whose cartesian coordinates are: .(3√3, 3)

Well, I know that: r² = sqrt(a² + b²)
. . so: r = 6
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . ._
and if we use: .tanθ .= .opp/adj /= .3/(3√3)
. . so: .tanθ = 1/√3

Then: .θ = π/6

So how do i know its π/6? . The point is in Quadrant I

How do i convert to get this answer with pi? radians?
I don't understand your question . . . the answer is in π.

Polar coordinates are: .(r, θ) .= .(6, π/6)