Hello, rcmango!

I don't understand your question . . . the answerFind polar coordinates of the point . . _

whose cartesian coordinates are: .(3√3, 3)

Well, I know that: rČ = sqrt(aČ + bČ)

. . so: r = 6

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . ._

and if we use: .tanθ .= .opp/adj /= .3/(3√3)

. . so: .tanθ = 1/√3

Then: .θ = π/6

So how do i know its π/6? . The point is in Quadrant I

How do i convert to get this answer with pi? radians?isin π.

Polar coordinates are: .(r, θ) .= .(6, π/6)