1. ## Revenue Function

I dont understand this question. Can you please tell me how to do the question, and help me with doing it?

The demand function for snack cakes at a large bakery is given by the function $\displaystyle p(x) = \frac{15}{2x^2+11x+5}$. The $\displaystyle x$-units are given in thousands of cakes, and the price per snack cake, $\displaystyle p(x)$, is in dollars.

a) Find the revenue function for the cakes

b) Estimate the marginal revenue for $\displaystyle x=0.750$. What is the marginal revenue for $\displaystyle x=2.00$?

I dont understand this question. Can you please tell me how to do the question, and help me with doing it?

The demand function for snack cakes at a large bakery is given by the function $\displaystyle p(x) = \frac{15}{2x^2+11x+5}$. The $\displaystyle x$-units are given in thousands of cakes, and the price per snack cake, $\displaystyle p(x)$, is in dollars.

a) Find the revenue function for the cakes

b) Estimate the marginal revenue for $\displaystyle x=0.750$. What is the marginal revenue for $\displaystyle x=2.00$?
The revenue function is R(x) = quantity * price = x * p(x).

Marginal Revenue refers to R'(x), the first derivative of Revenue.

Good luck!

3. What do you mean by "R(x) = quantity * price = x * p(x)." ???

4. Sure:

revenue = price times quantity

Example:
You sell 20 cds at ten dollars each:

x = quantity = 20 cds
p(x) = $10 R(x) = revenue = x * p(x) = 20 * 10 = 200 5. Thank you, but for some reason, the answer is soppsoe to be$\displaystyle
R(x) = \frac{15}{2x^2+11x+5}
$That is what it says in the Answers for that question 6. Originally Posted by haddad287 Thank you, but for some reason, the answer is soppsoe to be$\displaystyle
R(x) = \frac{15}{2x^2+11x+5}
$That is what it says in the Answers for that question That's the price function; the revenue function is product of the price function with quantity x, so if you throw in an x, you get revenue:$\displaystyle
R(x) = x \times p(x) = x \times \frac{15}{2x^2+11x+5} = \frac{15x}{2x^2+11x+5}
\$