# Thread: Transformations of Exponential Functions -

1. ## Transformations of Exponential Functions -

Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!

2. Originally Posted by woeckbr
Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!
Do you mean $y = 4^{x-1} - 2
$

If so from the graph of $4^x$ shift it 1 unit to the right and then move it 2 units down.

Therefore the asymptote at $y=0$ is now at $y=-2$

edit: see graph attached

3. Originally Posted by woeckbr
Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!
your transformation should be negative 2 shift down

$2=4^{x-1}$

$0 = 4^{x-1} -2$