# Transformations of Exponential Functions -

• Nov 28th 2009, 08:21 AM
woeckbr
Transformations of Exponential Functions -
Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!
• Nov 28th 2009, 08:30 AM
e^(i*pi)
Quote:

Originally Posted by woeckbr
Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!

Do you mean \$\displaystyle y = 4^{x-1} - 2
\$

If so from the graph of \$\displaystyle 4^x\$ shift it 1 unit to the right and then move it 2 units down.

Therefore the asymptote at \$\displaystyle y=0\$ is now at \$\displaystyle y=-2\$

edit: see graph attached
• Nov 28th 2009, 08:30 AM
11rdc11
Quote:

Originally Posted by woeckbr
Problem:

2=4^x-1

So For this transformation I thought you would complete a horizontal shift right one unit by adding 1 to all x-values and then a vertical shift up 2 units by adding 2 to the y-values -
our begining points are (0,1) (1,4) and (-1, 1/4) Im getting stuck transforming those points and my answers arent at all what they should be.... am I missing something?

thanks!

your transformation should be negative 2 shift down

\$\displaystyle 2=4^{x-1}\$

\$\displaystyle 0 = 4^{x-1} -2\$