1.) x^2/36 + y^2/12 = 1

Since a^2 = 36 because it is bigger

a= + or - 6

So vertex... SInce it lies on the x-direction: V(+/- a,0)

V_1(6,0)

V_2(-6,0)

2) How do I find the foci of the ellipse x[squared]/7 + y[squared]/16=1

c^2 = a^2 - b^2

c = \squareroot of (16 - 7)

c =\squareroot of 9

c= + or - 3

Foci... Since it lies on the y direction F(0, + or - c)

F_1 = (0, 3)

F_2 = (0,-3)