(1)$\displaystyle \frac{a+3}{3}+\frac{a-3}{6}=5$

(2)$\displaystyle \frac{3x+2}{2x-3}=\frac{3x-2}{2x-5}

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(3)$\displaystyle \frac{4m}{m-2}-\frac{13}{3m-6}=\frac{1}{3}$

(4)$\displaystyle \frac{1}{t-5}+\frac{1}{t+5}=\frac{8}{t^2-25}$

(5)$\displaystyle \frac{3}{2b+4}-\frac{4}{b-2}=\frac{3}{2b^2-8}$

(6)$\displaystyle \frac{3y+1}{4}=\frac{13-y}{2}$

Well I just completely failed my math test and i would like if anyone could help me so at least I could have an understanding of how to solve the following equations. I remeber learning how to solve the equations but not with equal signs