The point A(1;1;1) and the vector v->=(1;2;3).

Find the point B on the xy plane provided that v-> is collinear with AB->

My half-done solution:

AB->(x-1;y-1)

V->(1;2)

2x-y=1 (the result of cross product, I don't know the exact word in english)

So, what should be the x and y that they would be collinear. Maybe this approaching is wrong because of two unknown values.

Don't know what's next move.