loga X = C and logb X = D

i got it up to log ab X = (cd)/(c+d)

the question asked what the scope and/or limitations are. I know that ab and X can't be negatives but i dont know the rest

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- Nov 23rd 2009, 04:25 PMBzaherThe scope/limitation of logab X
loga X = C and logb X = D

i got it up to log ab X = (cd)/(c+d)

the question asked what the scope and/or limitations are. I know that ab and X can't be negatives but i dont know the rest - Nov 24th 2009, 03:12 AMstapel
I'm sorry, but I'm not clear on what you're being asked to do...? (Wondering)

Please reply with the full and exact text of the exercise, and the complete instructions. Thank you! (Wink) - Nov 24th 2009, 03:22 AMHallsofIvy
- Nov 24th 2009, 04:12 AMSoroban
Hello, Bzaher!

Quote:

$\displaystyle \log_a X \,=\, c,\;\;\log_b X \,=\, d$

i got it up to: .$\displaystyle \log_{ab} X \:=\:\frac{cd}{c+d}$

The question asked what the scope and/or limitations are.

*what?*

Here are the restrictions: .$\displaystyle \begin{Bmatrix}X \:>\:0 \\

a \,>\,0,\;a\,\neq\,1 \\ b\,>\,0,\;b\,\neq\,1 \\ c+d\,\neq\,0\end{Bmatrix}$