Solve for X: e^x(6-e^X)=9
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Originally Posted by VNVeteran Solve for X: e^x(6-e^X)=9 Distributing and rearranging, we get . Do you notice anything nice about this expression (don't think too hard about it)?
From where Chris left off consider a substitution giving Now you only need to solve a qudartic
Originally Posted by pickslides From where Chris left off consider a substitution giving Now you only need to solve a qudartic (a-3) (a-3) a=3 a=3 now what?
Originally Posted by VNVeteran (a-3) (a-3) a=3 a=3 now what? , so
it factors to take to both sides cancels out so you have
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