Results 1 to 3 of 3

Math Help - arithmetic sequence help

  1. #1
    Junior Member
    Joined
    Sep 2009
    Posts
    69

    Question arithmetic sequence help

    If the first three terms of an arithmetic sequence are \frac{4}{5}, \frac{38}{35}, \frac{336}{245} how do you find the nth term of the sequence?? i figured the bottom to be a_1 7^{n-1}
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    Nov 2009
    From
    Lebanon
    Posts
    26
    assume U0=4/5 U1=38/35 U2=336/245

    Un=U0+nr

    r=U1-U0=U2-U1= 10/35

    => Un= 4/5 + n ( 10/35 ) general term.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,707
    Thanks
    627
    Hello, Intsecxtanx!

    The first three terms of an arithmetic sequence are: . \frac{4}{5},\;\frac{38}{35},\;\frac{336}{245}
    How do you find the n^{th} term of the sequence?

    You should know that the n^{th} term is: . a_n \;=\;a_1 + (n-1)d

    . . where: . a_1 = first term, . d = common difference.


    The first term is: . a_1 \:=\:\frac{4}{5}

    The common difference is: . d \:=\:\frac{38}{35}-\frac{4}{5} \:=\:\frac{2}{7}

    Got it?

    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Arithmetic Sequence
    Posted in the Algebra Forum
    Replies: 4
    Last Post: April 21st 2011, 11:27 PM
  2. Replies: 2
    Last Post: August 24th 2010, 02:10 AM
  3. Arithmetic Sequence help!
    Posted in the Algebra Forum
    Replies: 2
    Last Post: March 15th 2009, 05:34 PM
  4. Arithmetic Sequence
    Posted in the Algebra Forum
    Replies: 1
    Last Post: November 19th 2008, 02:10 PM
  5. Replies: 12
    Last Post: November 15th 2006, 12:51 PM

Search Tags


/mathhelpforum @mathhelpforum