I have the function (this is exactly how it's written in the paper):
f(x)= -x^2/(x^2-9)
I need to know where exactly the negative is in the numerator:
-(x^2)
OR
(-x)^2
Which is right?
Any help is appreciated!
As mosta86 said, it doesn't matter:
$\displaystyle \frac{-x^2}{x^2-9}= \frac{x^2}{-(x^2- 9)}= -\frac{x^2}{x^2- 9}$.
In none of those, however, is this the same as $\displaystyle \frac{(-x)^2}{x^2- 9}= \frac{x^2}{x^2- 9}$.
I suspect that the question should NOT have been "is the negative in the numerator?" (the answer to that is "it doesn't matter") but "is the negative part of what is squared?". The answer to that is NO! For example, $\displaystyle -2^2= -(2)(2)= -4$ NOT $\displaystyle (-2)(-2)= 4$.