(6cos[pi/3],6sin[pi/3])
Hello, rcmango!
There are formulas for this problem.Find the cartesian coordinates of the points with polar coordinates (6, π/3)
Given polar coordinates: .(r, θ)
. . x .= .r·cosθ
. . y .= .r·sinθ
We are given: .r = 6, .θ = π/3
Hence: . x .= .6·cos(π/3) .= .6(1/2) .= .3
. . . . . . y .= .6·sin(π/3) .= .6(sqrt{3}/2) .= .3sqrt{3}
. . . . . . . . . . ._
Answer: .(3, 3√3)