Please help on finding:

the slope of the given points:

1.) (3/4 , -2) ; (2 , 2/3)

2.) (0 , 2/3) ; (3 , 0)

the equation of the line with two given points:

1.) (3/4 , 0) ; (0 , 4/3)

2.) (3/5 , 2) ; (5 , 2/3)

thanks, ;-)

Printable View

- Feb 13th 2007, 05:09 AMAussieboyfind slope
Please help on finding:

the slope of the given points:

1.) (3/4 , -2) ; (2 , 2/3)

2.) (0 , 2/3) ; (3 , 0)

the equation of the line with two given points:

1.) (3/4 , 0) ; (0 , 4/3)

2.) (3/5 , 2) ; (5 , 2/3)

thanks, ;-) - Feb 13th 2007, 05:43 AMtopsquark
- Feb 13th 2007, 05:51 AMtopsquark
A standard for the form of a line is the slope-intercept form:

y = mx + b

where m is the slope of the line and b is the y-intercept: the point (0, b).

For the first problem we have a slope of:

m = (4/3 - 0)/(0 - 3/4) = (4/3)/(-3/4) = -16/9

So we know that the line is of the form:

y = -(16/9)x + b

Consider our first point on this line: (3/4, 0). Inserting this point into our line equation gives us:

0 = -(16/9)(3/4) + b

Solving for b:

0 = -(4/3) + b

b = 4/3

Thus the line is

y = -(16/9)x + (4/3)

You do the second one. I get that y = -(10/33)x + (24/11)

-Dan