If (square root of 4+x) + (square root of 10-x) = 6. Then solve (square root (4+x)(10-x)). (4+x)^(1/2) + (10-x)^(1/2) = 6. Then solve (4+x)(10-x)^(1/2)
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Originally Posted by crystaly0x If (square root of 4+x) + (square root of 10-x) = 6. Then solve (square root (4+x)(10-x)). (4+x)^(1/2) + (10-x)^(1/2) = 6. Then solve (4+x)(10-x)^(1/2) Let Therefore, a + b = 6 2ab = 36 - (4 + x) - (10 - x) 2ab = 22 ab = 11 hence = 11
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