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Math Help - Solving for x

  1. #1
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    Solving for x

    I'm not sure how to solve this question:

    2^2x - 3(2^x) +2 = 0

    Appreciate any help

    Thanks
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  2. #2
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    Quote Originally Posted by Neconine View Post
    I'm not sure how to solve this question:

    2^2x - 3(2^x) +2 = 0

    Appreciate any help

    Thanks
    Let y = 2^x
    So we have y^2 - 3y + 2 = 0
    (y - 2)(y - 1) = 0
    y = 2 or y = 1
    Therefore 2^x = 2, x = 1
    or 2^x = 1, x = 0
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  3. #3
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    Quote Originally Posted by ukorov View Post
    Let y = 2^x
    So we have y^2 - 3y + 2 = 0
    (y - 2)(y - 1) = 0
    y = 2 or y = 1
    Therefore 2^x = 2, x = 1
    or 2^x = 1, x = 0
    Thanks a lot!
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