I'm not sure how to solve this question: 2^2x - 3(2^x) +2 = 0 Appreciate any help Thanks
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Originally Posted by Neconine I'm not sure how to solve this question: 2^2x - 3(2^x) +2 = 0 Appreciate any help Thanks Let y = 2^x So we have y^2 - 3y + 2 = 0 (y - 2)(y - 1) = 0 y = 2 or y = 1 Therefore 2^x = 2, x = 1 or 2^x = 1, x = 0
Originally Posted by ukorov Let y = 2^x So we have y^2 - 3y + 2 = 0 (y - 2)(y - 1) = 0 y = 2 or y = 1 Therefore 2^x = 2, x = 1 or 2^x = 1, x = 0 Thanks a lot!
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