$\displaystyle (1) 12x^3-3xy^2$
Thought it factored out to get $\displaystyle 3x(4x^2-y^2)$
but I got it wrong... so whats the write way?
$\displaystyle (1) 12x^3-3xy^2$
Thought it factored out to get $\displaystyle 3x(4x^2-y^2)$
but I got it wrong... so whats the write way?