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Thread: Factorizing

  1. #1
    Member purplec16's Avatar
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    Factorizing

    $\displaystyle (1) 12x^3-3xy^2$
    Thought it factored out to get $\displaystyle 3x(4x^2-y^2)$
    but I got it wrong... so whats the write way?
    Last edited by purplec16; Nov 15th 2009 at 09:21 AM. Reason: found out the answer for a problem on my own
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  2. #2
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    Quote Originally Posted by purplec16 View Post
    $\displaystyle (1) 12x^3-3xy^2$
    Thought it factored out to get $\displaystyle 3x(4x^2-y^2)$
    but I got it wrong... so whats the write way?
    you didn't finish ... $\displaystyle (4x^2-y^2)$ is also factorable
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  3. #3
    Member purplec16's Avatar
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    Oh...

    Thanks, my mistake... so it would be $\displaystyle 3x(2x+y)(2x-y)$
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