y = f(x) = x^3 - 8

**shenton** · February 9th 2007, 08:31 PM

y = f(x) = x^3 - 8

Write an equation which represents y = f-1(x).

The -1 in f-1 is in supercript form, which I think stands for inverse.

This one is harder as it is a cubic expression. How to solve this?

Thanks.

**earboth** · February 9th 2007, 08:41 PM

Originally Posted by shenton

y = f(x) = x^3 - 8

Write an equation which represents y = f-1(x)....

Hello,

from $f(x)=x^3-8$ you get

$f^{-1}: x=y^3-8 \Longrightarrow f^{-1}: x+8=y^3 \Longrightarrow f^{-1}: \sqrt[3]{x+8}=y$

EB

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y = f(x) = x^3 - 8