so from (x+5)(x-5) would I then make the other side e^0 giving me 1?
Does (x+5)(x-5) become x^2-25?
Yes and Yes (it's the difference of two squares) so you get $\displaystyle x^2-26=0$. As 26 is 2*13 it will no break down to be simpler than $\displaystyle \sqrt{26}$