# Solve for time, t

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• Nov 12th 2009, 09:59 AM
mathtutor101
Solve for time, t
Please help me solve this equation, for time t (exponent). I know you have to use natural log (ln) but I am unable to use the rules correctly.

p = x + (y-x)(1-m)^t

If it helps, y=.42 x=.12 m=.07 and p should be .12, but i would like to see the equation solved for time, t, with the variables given above.
• Nov 12th 2009, 10:30 AM
Raoh
hi(Happy)
$(1-m)^{t}=\frac{p-x}{y-x}\Rightarrow t=\log_{1-m}\left (\frac{p-x}{y-x} \right )$
• Nov 12th 2009, 10:43 AM
Raoh
u also have,
$t= \frac{\ln (\frac{p-x}{y-x})}{\ln (1-m)}$
• Nov 12th 2009, 02:08 PM
mathtutor101
Thank you both I really appreciate it!